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[tex]daca f:(-\infty, 0) ->R si \sqrt{(m-3)x^{2}-2(2m-5)x+m-3 [/tex]

cum se aleg delta si a?



Răspuns :

[tex]a=m-3\\ b=-2(2m-5)\\ c=m-3\\ \triangle=b^2-4ac=4(4m^2-20m+25)-4(m^2-6m+9)\\ \triangle=16m^2-80m+100-4m^2+24m-36\\ \triangle=12m^2-56m+64[/tex]