CaCO3 ---> CaO + CO2
puritatea = masa pura/masa impura * 100 (puritatea = 80%)
masa pura = 80*1000 kg/100 = 800 kg CaCO3
100 g CaCO3........56 g CaO.........1 mol CO2
800 kg CaCO3.......x kg CaO........y kmoli CO2
x = 448 kg CaO - pt intrebarea a
y = 8 kmoli CO2 - pt intrebarea b
CaO + H2O ---> Ca(OH)2
56 g CaO............74 g Ca(OH)2
448 kg CaO...........z kg Ca(OH)2 z = 592 kg Ca(OH)2
c=md/ms*100 => ms = md/c*100=592/2 * 100 = 29600 kg = 29,6 kg solutie
