[tex]1) \sqrt{(1-3x)^2} =7\\
|1-3x|=7\\
1-3x=7\ \ si \ 1-3x=-7\\
3x=-6\ si\ 3x=8\\
x_1=-2\ si \ x= \frac{8}{3} \\[/tex]
[tex]2)(\sqrt{3}-1)^2-2(\sqrt{3}+2,(5))+4|1-\sqrt{3}|=\\
=3-2 \sqrt{3} +1-2 \sqrt{3} -2\cdot 2 \frac{5}{9} -4+4\sqrt{3}=\\
=-2\cdot 2 \frac{5}{9}=-2\cdot \frac{23}{9} =- \frac{46}{9}
[/tex]
