👤

Ma poate ajuta cineva?

Ma Poate Ajuta Cineva class=

Răspuns :

[tex]a=2\sqrt{3}-2 * 3\sqrt{3} + 5\sqrt{3} + 4\sqrt{3} +2 *5\sqrt{3} = \\ = 2\sqrt{3}-6\sqrt{3}+5\sqrt{3} +4\sqrt{3} + 10\sqrt{3}=\ \textgreater \ a = 15\sqrt{3}[/tex]
[tex]b = |5-\sqrt{3}| - |2\sqrt{3}-3\sqrt{2}| - |5-3\sqrt{2}| + \sqrt{(7-1)(7+1)} = \\ = 5-\sqrt{3}-(3\sqrt{2}-2\sqrt{3})-(5-3\sqrt{2})+\sqrt{6*8} = \\ = 5-\sqrt{3}-3\sqrt{2}+2\sqrt{3}-5+3\sqrt{2}+4\sqrt{3} =\ \textgreater \ b =5\sqrt{3}[/tex]
[tex]m_g=\sqrt{a*b} =\ \textgreater \ m_g=\sqrt{15\sqrt{3}*5\sqrt{3}} = \sqrt{15*5*3} = \sqrt{15*15} =\ \textgreater \ \\ =\ \textgreater \ m_g=15.[/tex]