Notam prima fractie cu t si vom obtine ecuatia
t+1/t=5/2 aducem la acelasi numitor, numitorul comun fiind 2t
2t²+2=5t
2t²-5t+2=0
Δ=25-16=9
t1/2=(5+-3)/4
t1=2
t2=1/2
(x²+1)/x=2
x²+1=2x
x²-2x+1=0
Δ=0
x1/2=-b/2a=1
(x²+1)/x=1/2
2x²+2=x
2x²-x+2=0
Δ<0=> in acest caz ecuatia nu are solutii reale.
S={1}
