[tex]\sqrt[4]{x-2} +2\sqrt{x-2} -3 = 0 \\\;\\
Notam\ \sqrt[4]{x-2}=y,\ y\ \textgreater \ 0,\ iar\ ecuatia\ devine:[/tex]
[tex]2y^2+y-3=0[/tex]
Rezolvam ecuatia si retinem doar solutia pozitiva y = 1.
Revenim asuprea notatiei si obtinem :
[tex]\sqrt[4]{x-2} = 1 \Rightarrow x-2=1 \Rightarrow x=3.[/tex]
