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(1+2a-a+ax0+ax1+a):10=10

Răspuns :


(1+a+a+a):10=10

1+3a=100

3a=100-1

3a=99

a=33

(1 + 2a - a + a * 0 + a * 1 + a) : 10 = 10
1 + a + 0 + a + a = 10 * 10
3a = 100 - 1
a = 99 : 3
a = 33