[tex] \frac{12}{ \sqrt{3} } = \frac{12 \sqrt{3} }{3} = 4 \sqrt{3}
[/tex]
[tex]- \frac{9}{3 \sqrt{3} } = - \frac{9 \sqrt{3} }{9} = - \sqrt{3} [/tex]
[tex] \frac{16}{2 \sqrt{2} } = \frac{16 \sqrt{2} }{4} = 4 \sqrt{2} [/tex]
[tex] \frac{42}{2 \sqrt{7} } = \frac{42 \sqrt{7} }{14} = 3 \sqrt{7} [/tex]
[tex] \frac{18}{2 \sqrt{3} } = \frac{18 \sqrt{3} }{6} = 3 \sqrt{3} [/tex]
[tex] \frac{12}{3 \sqrt{2} } = \frac{12 \sqrt{2} }{6} = 2 \sqrt{2} [/tex]
[tex] \frac{36}{3 \sqrt{6} } = \frac{36 \sqrt{6} }{18} = 2 \sqrt{6} [/tex]
[tex] \frac{-21} \sqrt{7} } = \frac{21 \sqrt{7} }{7} } = 3 \sqrt{7} [/tex]
asa trebuie facute si celelalte. sper ca ai inteles. as vrea sa ti le rezolv si pe celelalte, dar nu am timp. mult noroc la teme. :)
