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10 supra √6 + 1 ,  -3 supa 1-√7  Ajuta-ma

Răspuns :

[tex] \frac{10}{ \sqrt{6}+1 } = \frac{10( \sqrt{6}-1) }{6-1} = \frac{10( \sqrt{6}-1) }{5} =2( \sqrt{6}-1)=2 \sqrt{6}-2 [/tex]

[tex] \frac{-3}{1- \sqrt{7} } = \frac{-3(1+ \sqrt{7}) }{1-7} = \frac{-3( 1+\sqrt{7} )}{-6} = \frac{1+ \sqrt{7} }{-2} [/tex]