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ecuatia
(x+5)(x+3)=(x-1)(x+7)+10
(x+5)(x-5)=(x+1)(x+3)+12


Răspuns :

Intre paranteze este inmultire?
x^2+3x+5x+15 =x^2+7x-x-7+10
x^2+8x-x^2-6x=3-15
2x=-12
x=-6


x^2-25=x^2+3x+x+3+12
x^2-x^2-4x=15+25
-4x=40
-x=10
x=-10