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comparati numerele naturale x=[1+2ori (18:6+2ori 5)]-50:10 si y=(4+3)la puterea a 2a-(2la puterea a 3a-2)ori 3 - 2 la puterea 0
pliz va rog ajutatima e urgent


Răspuns :

x=[1+2x(3+10)]-5
x=1+60-5
x=56
y=(16+9)-(8-2)x3-1
y=25-6x3-1
y=6

x<y
x=1+2*(3+10)-5
x=1+2*13-5
x=1+26-5
x=22
y=49-(8-2)*3-1
y=49-6*3-1
y=49-18-1
y=30
x<y