a. d( A ; BC) = cateta AB
AB² = AC² - BC² = 10² - 6² =100- 36 = 64 : AB = √64 = 8 cm
b . daca MA⊥ AB ( din ipoteza)
si AB ⊥ BC ( mas∡B = 90° ) atunci , MB ⊥ BC ( teorema 3⊥)
c. Δ MAC ; m∡MAC =90°
MB² = MA² + AB² = 6² + 8² =36 +64 =100
MB = √100 cm = 10 cm