11<7(a-5)<=25
Luam prima inecuatie :
11<7(a-5)-3, 7a-35-3>11, 7a>11+38, 7a>49, a>49/7,
a>7, a€{8,9,10,...}
Luam si a doua inecuatie :
7(a-5)-3<=25
7a-35-3<=25
7a<=25+38
7a<=63, a<=63/7, a<=9
a€{0,1,2,3,4,5,6,7,8,9}
Deci, dupa rezolvarea celor 2 inecuatii, avem : a€{8,9}