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Aflati numarul necunoscut:
3+3x[3+3x(3+3x3)]=(3xa+3)x3+3


Răspuns :

Răspuns: [tex]\purple{\boxed{~\bf a = 12~}}[/tex]  

Explicație pas cu pas:

[tex]\bf 3+3\cdot [3+3\cdot(3+3\cdot3)]=(3\cdot a+3)\cdot3+3[/tex]

[tex]\bf 3+3\cdot [3+3\cdot(3+9)]=9a+9+3[/tex]

[tex]\bf 3+3\cdot (3+3\cdot12)=9a+9+3[/tex]

[tex]\bf 3+3\cdot (3+36)=9a+12[/tex]

[tex]\bf 3+3\cdot 39 =9a+12[/tex]

[tex]\bf 3+117 =9a+12[/tex]

[tex]\bf 120 =9a+12[/tex]

[tex]\bf 120 -12 =9a[/tex]

[tex]\bf 108 =9a[/tex]

[tex]\bf 9a = 108 ~~~\bigg|:9[/tex]

[tex]\purple{\boxed{~\bf a = 12~}}[/tex]

[tex]==pav38==[/tex]