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1) Rezolvati in multimea numerelor rationale ecuatia :

3(x+5)-6(x-2)=4(x+2)-5(x-4)


Răspuns :

3x+15-6x+12=4x+8-5x+20
-3x-4x+5x=8+20-15-12
-7x+5x=28-27
-2x=1
x=-1/2
Eliminam parantezele efectuand inmultirile si obtinem:

[tex]3x+15-6x+12 = 4x+8-5x+20[/tex]


Separam necunoscuta:

[tex]3x-6x-4x+5x= 8+20-15-12[/tex]


Efectuam calculele si obtinem:

[tex]-2x= 1 |_{\cdot (-1)} \Longrightarrow\ 2x= - 1\ \Longrightarrow\ x=-\dfrac{1}{2}[/tex]