1. f , g : R -----> R
( fog)(x) = f( g(x)) = 3g(x) - 5 = 3 · ( x + 5 /3 ) - 5 = 3x + 15 /3 - 5 =
= 3x +5 - 5 = 3x ≠ x ⇒ f nu are inversa g
2. f : R \ { 2 } ---> R g : R \ { 1} ----> R
(fog)(x) = f(g(x)) = g(x) / [ g(x) -2 ] = 2x · ( x -1) / ( x -1) ·( 2x -2x + 2) =
= 2x /2 = x f are inversa functia g