Uite rezolvarea problemei:
Utilizatorul care mai a raspuns a raspuns corect! Felicitari!
#include<iostream.h>
#include<stdio.h>
#include<conio.h>
unsigned a[20][20] ,i, j, n, m, q=0, p=1,c;
int main()
{
clrscr();
cout<<"n="; cin>>n;
cout<<"m="; cin>>m;
cout<<"c="; cin>>c;
for(i=1;i<=n;i++)
for(j=1;j<=m;j++)
{
cout<<"a["<<i<<"]["<<j<<"]=";
cin>>a[i][j];
}
for(i=1;i<=n;i++)
for(j=1;j<=m;j++)
if(a[i][j]<c)
q++;
else
if(a[i][j]>c)
p=p*a[i][j];
cout<<"Sunt "<<q<<" elemente mai mici ca "<<c<<" si produsul elementelor mai mari ca "<<c<<" este "<<p;
getch();
}
