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(7/32+1/40+6/96):71/480

Răspuns :

[tex]\left( {\dfrac{^{15)}7}{\ 32}} +\dfrac{^{12)} 1}{\ 40}+\dfrac{^{5)}6}{\ 96}\right):\dfrac{71}{480}=\dfrac{105+12+30}{480}\cdot\dfrac{480}{71}[/tex]

Se efectueaza adunarile si se simplifica prin 480