1.
a+b+c=510
b=a/2
c=a+b+24
c=a/2+a+24
inlocuim
a+a/2+a/2+a+24=510
aducem la numitor comun
2a+a+a+2a+48=1020
6a=1020-48
6a=972
a=162 km
b=81
c=162+81+24=267
ver.162+81+267=510
2.
a+b+c=155
a=b/3
c=11+b-a
c=11+b-b/3
inlocuim
b/3+b+11+b-b/3=155
2b=144
b=72
a=24
c=72-24+11=59
ver.24+72+59=155
3.(a+b+c)/2=115
b=a-25
c=2(a+b)
c=2(a+a-25)
c=4a-50
inlocuim
(a+a-25+4a-50)/2=115
nu o pot rezolva mai departe,cred ca e ceva gresit.
4.
a+b+c=110
b=5a-23
c=b+10
c=5a-23+10=5a-13
inlocuim
a+5a-23+5a-13=110
11a=146
ca la problema nr. 3,da cu virgula