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Calculaţi raza cercului inscris in triunghiul ABC cu AB=AC=5,si BC=8.

Răspuns :

[tex]r= \frac{Sabc}{p} [/tex]
[tex]p= \frac{AB+AC+BC}{2} = \frac{5+5+8}{2} =9[/tex]
[tex]Sabc \sqrt{p(p-AB)(p-BC)(p-AC)} = \sqrt{9*(9-5)(9-5)(9-8)} =12[/tex]
[tex]=|\ \textgreater \ r= \frac{12}{9} = \frac{4}{3} [/tex]