Răspuns:
M,CH3COOH= 60g/mol
Vm= 22,4L/mol
2mol.................1mol.....................................1mol
2CH3-COOF + Fe----> (CH3COO)2Fe + H2
x.........................0,1mol.................................y
x= 0,2mol acid acetic
m=niuxM=0,2x60g= 12g acid acetic
y=0,1molH2
V=niuxVm= 0,1x22,4 l=2,24 l H2
Explicație: