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Aflati numerele x, y, z daca x+y+z=132, iar x-z=y+z si z=y:4 . Multumesc !


Răspuns :

x + y + z = 132
x - z = y + z
z = y : 4     => y = 4z
x - z = 4z + z
x = 6z
6z + 4z + z = 132
11z = 132
z = 132 : 11
z = 12
x = 6 * 12
x = 72
y = 4 * 12
y = 48