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aratati ca [tex] \frac{1}{4+2 \sqrt{3} } + \frac{1}{4-2 \sqrt{3} }=2[/tex]

Răspuns :

[tex] \frac{4-2 \sqrt{3}+4+2 \sqrt{3} }{(4+2 \sqrt{3})(4-2 \sqrt{3}) }= \frac{8}{16-12} = \frac{8}{4}=2 [/tex]