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DAU COROANA
Descompuneti in factori ireductibili :
x^2+12x+35


Răspuns :

fie x1, x2 rad ec x²+12x+35=0
x1+x2=-12 x1*x2=35 deci rad vor fi -5 si -7

reorganizam x²+5x+7x+35= x(x+5)+7(x+5)= (x+5)(x+7)

O zi buna!
Descompunem pe 12x in 5x+7x=> x patrat+5x+7x+35=x(x+5)+7(x+5)=(x+5)(x+7)