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[tex] \sqrt{7- 2\sqrt{6} }[/tex] =?
o rezolvare completa,va rog!Seara frumoasa:)


Răspuns :

[tex]\sqrt{7-2\sqrt{6}}= \sqrt{7-\sqrt{24}} \\ \\ A=7 \\ B=24 \\ \\ C^2=49-24=25 => \boxed{C=5} \\ \\ \sqrt{7-2\sqrt{6}}= \sqrt{\frac{7+5}{2}-\sqrt{\frac{7-5}{2}}}= \sqrt{\frac{12}{2}-\sqrt{\frac{2}{2}}}= \sqrt{6}-1[/tex]