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a). x=3supra20; y+8=1supra4. Calculati (x+y)+8.
b). x+y=1supra3 , y+2z=3supra5 . calculate 2x+3y+2z.
Multumesc!


Răspuns :

a)(x+y)+8=x+(y+8)=3/20+1/4=(3+5)/20=8/20=2/5


b)2x+3y+2z=2x+2y+y+2z=2(x+y)+(y+2z)=2*1/3+3/5=(10+9)/15=19/15