1.x(x-1)-(x-5)²=2
x²-x-(x²-10x+25)=2
x²-x-x²+10x-25-2=0
9x-27=0
9x=27
x=27/9
x=3
S={3};
2.16x(2-x)+(4x-5)²=0
32x-16x²+16x²-40x+25=0
-8x=-25
x=-25/-8
x=3 intregi 1/8 ("/" sub foma de fractie)
3.(x-5)²-x²=3
x²-10x+25-x²=3
-10x+22=0
-10x=-22
x=-22/-10
x=2.2
4.(2x+1)²-4x²=5
4x²+4x+1-4x²=5
4x+1=5
4x=4
x=4/4
x=1
5.9x²-1-(3x-2)²=0
9x²-1-(9x²-12x+4)=0
9x²-1-9x²+12x-4=0
12x=5
x=5/12(forma de fractie)
6.x+(5x+2)²=25(1+x)²
x+(25x²+20x+4)=25(1+2x+x²)
x+25x²+20x+4=25+50x+25x²
x+25x²+20x-50x-25x²=25-4
-29x=21
x=-21/29(fractie)
Sper ca n-am comis greseli.
