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Determinaţi valoarea numărului J ştiind că:
150-(150:150+147:147+144:144+...+J:J)=102


Răspuns :

Notam (150:150+147:147+144:144+...+J:J) cu x
150-x=102
x=150-102=48
x=(150:150+147:147+144:144+...+J:J)=48
x=1*[(150-J):3+1]=48
(150-J):3+1=48
(150-J):3=49
150-J=147
J=3