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3+3x[3+3x(3+3x3)]=(3xa+3)X3+3=

Răspuns :

Desfacem parantezele
3+3x[3+3x(3+9)]=(3xa+3)x3+3=
3+3x(3+3x12)=(3xa+3)x3+3=
3+3x(3+36)=(3xa+3)x3+3=
3+3x39=(3xa+3)x3+3=
117=(3xa+3)x3+3-3
deci 3xa+3=117:3=39
3xa=39-3=36
a=36:3=12