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(1+√2) totul la a 2 + (1-√2) totul la a 2 ...este numar natural

Răspuns :

[tex](1+ \sqrt{2} )^ 2+(1- \sqrt{2} )^ 2=1^ 2+2 \cdot 1 \cdot \sqrt{2} + \sqrt{2^2} +1^2-2 \cdot 1 \cdot \sqrt{2} + \sqrt{2^2} = \\ =1+2 \sqrt{2} +2+1-2 \sqrt{2} +2=1+2+1+2=6 \in N[/tex]
(1+√2)²+(1-√2²)=1²+√2²=1+2=3