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(-9supra10):(18supra25)-(+3supra5):21supra20

Răspuns :

Sper sa intelegi cum am facut !! :))
Vezi imaginea MAI2001
 [tex](-\frac{\not9^1}{\not{10}_2})\cdot\frac{\not{25}^5}{\not{18}_2}\,-\,\frac{\not3^1}{\not5_1}\cdot\frac{\not{20}^4}{\not{21}_7}=\frac{-5}{4}-\frac{4}{7}=\frac{-35-16}{28}=-\frac{51}{28}[/tex]