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Va roog! <3 am nevoie urgenta!



Va Roog Lt3 Am Nevoie Urgenta class=

Răspuns :

2.  [tex]a) \frac{12}{3 \sqrt{3}} = \frac{4}{ \sqrt{3}}= \frac{4 \sqrt{3}}{3} [/tex]
[tex]b) \frac{21}{ \sqrt{14}} = \frac{21 \sqrt{14}}{14} = \frac{3 \sqrt{14}}{2} [/tex]
[tex]c) - \frac{28}{4 \sqrt{7}} =- \frac{14}{2 \sqrt{7}} =- \frac{7}{ \sqrt{7}} =- \frac{7 \sqrt{7}}{7} =- \sqrt{7} [/tex]
[tex]d) \frac{ \sqrt{2}}{ \sqrt{3}} = \frac{ \sqrt{6}}{3} [/tex]
[tex]e) \frac{ \sqrt{6}}{2 \sqrt{2}} = \frac{ \sqrt{12}}{4} = \frac{2 \sqrt{3}}{4} = \frac{ \sqrt{3}}{2} [/tex]
[tex]f) \frac{5 \sqrt{3}}{4 \sqrt{5}} = \frac{5 \sqrt{15}}{20} = \frac{ \sqrt{15}}{4} [/tex]
3.[tex] \frac{12}{\sqrt{2}} - \frac{14}{ \sqrt{8}} + \frac{16}{ \sqrt{32}} - \frac{18}{3 \sqrt{2}} =[/tex][tex] \frac{12 \sqrt{4}}{ \sqrt{8}} - \frac{14}{ \sqrt{8}}+ \frac{16}{ \sqrt{32}} - \frac{18}{3 \sqrt{2}} [/tex]
Cu ce sa te ajut? Nu văd problema.