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Pe o dreapta consideram punctele A,B SI C.Notam cu E SI F mijloacele segmentelor [AB] SI [AC] .DACA AB =6,4 CM SI AC=10 CM AFLATI BF SI Ef

Răspuns :

BF=6,4-(10:2)=1,4cm
EF=5-3,2=1,8cm

                                                          10        

                                   6,4                                                    3,6
-------A----------------------!--------------------------B-------------------!-------------------C----------------

                                   E                                                        F

                                                            Rezolvare

BC=AC-AB=10-6,4=3,6 cm

AE=BE=6,4/2=3,2 cm

BF=CF=3,6/2=1,8 cm

EF=EB+BF=3,2+1,8=5 cm

                                    R-s:  BF=1,8cm=18 mm   EF=5cm