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In triunghiul ABC oarecare, se duc: AD ⊥ BC, D ∈ (BC) si BE ⊥ AC, E∈ (AC)
a) Daca AC= 16 cm, BE=9cm , AD= 8cm, calculati A indice triungiul ABC si BC
b) Daca AC=15cm, BC=9cm, AD=10cm, calculati A indice triungiul ABC si BE
c) Daca A indice triunghiu ABC = 45,5 cm^2, AD=7cm, AC=13cm, calculati BC,BE


Răspuns :

A=bxh/2

A)Aabc=BExAC/2=ADXBC/2
A=BEXAC/2=9x16/2=72cm² dar si ADXBC/2=72⇒8xBC/2=72⇒BC=2x72/8=18
b)Aabc=ADXBC/2=10x9/2=45
BExAC/2=45⇒BEx15/2=45⇒BE=45x2/15=6
c)Aabc=BExAC/2⇒45,5=BEx13/2⇒BE=45,5x2/13=7
Aab=ADXBC/2⇒45,5=ADx7/2⇒AD=45,5x2/7=13 succes ... coronita -------------