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sinX=?  cosX=4/5  X apartine (0 grade,90 grade)



Răspuns :

sin(x)²+cos(x)²=1
sin(x)²+4÷5²=1
sin(x)²=1-14÷25=9÷25
sin(x)=3÷5
[tex]sin^2x+cos^2x=1\\ sin^2x=1- \frac{16}{25} = \frac{9}{25} \\ sinx=\pm \sqrt{\frac{9}{25}} =\pm \frac{ 3 }{5} \\ Deoarece\ x\in(0^0;90^0)=>sinx=\frac{ 3 }{5}[/tex]