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rezolvati:3y-2x+10z, 7x+10y+6z=, 4(2z+y)+3x+3y=

Răspuns :

x+y=8
y+2z=35

3y-2x+10z=-2x-2y+2y+3y +10 z=-2(x+y) + 5(y+2z)=-2*8+5*35=-16+175=159
am adunat si am scazut 2y

 7x+10y+6z= 7x+7y+3y+6z=7(x+y)+3(y+2z)=7*8+3*35=56+105=161

 4(2z+y)+3(x+y)=4*35+3*8=140+24=164