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cum se afla 3+x=4intregi si 1pe2

Răspuns :

3+x=9/2
x=9/2-3
x=9/2-6/2
x=3/2
3+x=(4*2+1)/23+x=9/2amplific in stanga cu 2 adica inmultesc cu 2 ca sa renunt la numitor6+2x=9 ↑-66+2x-6=9 -62x=3↑:2
x=3/2