| 2x-3 | ≤ 5 => -5≤2x-3≤5 => -2≤2x≤8 => -1≤x≤4 => A= { -1,0,1,2,3,4}
(x-2)/ (x+2) ∈ Z x-2 - multiplu al x+2
Ne intereseaza intersectia multimilor ,
verificam folosind valorile din a
x=-1
> -1-2/-1+2∈Z
x=0
> 0-2/0+2 ∈Z
x=1
>1-2/1+2∈Z
x=2
>2-2/2+2 ∈Z
x=3
> 3-2/2+3∉Z
x=4
> 4-2/4+2∉Z
=> A∧B={ -1,0,1,2} si A-B={ 3,4}
