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Calculati!!
a)√2(√2+√3) - √3(2√3+√2)=


Răspuns :

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2+rad6-6-rad6=-4
[tex] \sqrt{2} ( \sqrt{2} + \sqrt{3} )- \sqrt{3} (2 \sqrt{3} + \sqrt{2} )= \\ =2+ \sqrt{6} -6- \sqrt{6} = \\ =2-6= \\ =-4 [/tex]