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[tex](x+y-1)la puterea 5018,daca x=1+a si y=1-a[/tex]

Răspuns :

   
[tex]x=1+a \\ y=1-a \\ (x+y-1)^{5018} = (1+a+1-a-1)^{5018}= \\ =(1+1-1+a-a)^{5018}= 1^{5018}=\boxed{1}[/tex]