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Determinati numarul natural a:

a)2 x (3a+2)-22=5 x (a+1)+78
b) [5 x (2 x a+3)+4x(2 x a+3)]:5=27


Răspuns :

A) 6a+4-22=5a+5+78. / 6a-5a=5+78+22-4. / a=134. / B) (2a+3)(5+4)=27*5. / (2a+3)*9=135. / 2a+3=15. /2a=12. / a=6