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Sa se calculeze (2+i)(3-2i) - (1-2i ) (2-i)

Răspuns :

[tex]\displaystyle (2+i)(3-2i) - (1-2i ) (2-i)=\\ =(6-4i+3i-2i^2)-(2-i-4i+2i^2)=\\ (6-i+2)-(2-5i-2)=6-i+2-2+5i+2=8+4i[/tex]