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Determinati 4x + 10y + 3z, stiind ca 2x + 3y = 17 si 4y + 3z = 74

Răspuns :

2x +3y = 17
inmultesc cu 2 in ambele parti:
⇒4x +6y = 34

4x+6y =34
4y +3z =74
-----------------------le adun:
⇒4x+10y+3z = 34+74
4x+10y+3z = 108
2·(2x +3y) + 4y+3z =2·17 + 74
4x + 6y +4y +3z = 108
4x + 10y + 3z = 108