👤

Calculati aplicind formulele (a+b)^2=a^2+2ab+b^2 (a-b)^2= a^2-2ab+b^2
radical(7+4radical din 3 ) + radical(7-4 radical din 3)
.


Răspuns :

[tex]\sqrt{7+4 \sqrt{3} } = \sqrt{4+4 \sqrt{3}+ \sqrt{3^2} } = \sqrt{(2+ \sqrt{3})^2 } =2+ \sqrt{3}[/tex]
[tex] \sqrt{7-4 \sqrt{3} } = 2- \sqrt{3} (dupa formula (a-b)^2 )[/tex]
[tex]2+ \sqrt{2} +2- \sqrt{3} = 4[/tex]