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Un biciclist parcurge prima zi 2/3 din drum. A doua zi parcurge 1/9 din rest. A treia zi 8km. Cat a parcurs in cele3 zile?


Răspuns :

a+b+c=x
a=2/3x
b=1/9(x-2/3x)=1/9*1/3x=1/27x
c=8
2/3x+1/27x+8=x
18x+x+216=27x
19x-27x=-216
-8x=-216
x=216/8
x=27
a=2/3*27=18
b=1/27*27=1
proba
18+1+8=27 km