3√6/(3√2+2√3)-5√6/(4√3+3√2)-√6/(5√3-6√2)=
rationalizam numitorii
=3√6(3√2-2√3)]/(18-12)-[5√6(4√3-3√2)]/(48-18)-[√6(5√3+6√2)]/(75-24)=
=[(9√12-6√18)/6-[(20√18-15√12)]/30-[(5√18+6√12)]/51=aducem la acelasi numitor=
=[85(18√3-12√2)-17(60√2-30√3)-10(15√2+12√3)]/510=
=[1530√3-1020√2-1020√2+510√3-150√2-120√3]/510=
=(1920√3-2190√2)/510=10(192√3-219√2)/510=(192√3-219√2)/51=
=3(64√3-73√2)/51=(64√3-73√2)/17