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Daca x+y=1,calculati:
(2x+2y)+(3x+3y)²+(4x+4y)³=?

As vrea razolvarea completa, va rog! 


Răspuns :

Daca x+y=1,calculati:
(2x+2y)+(3x+3y)²+(4x+4y)³=?

[2(x+y)]+[3(x+y)]^2+[4(x+y)]^3

dar cum x+y=1, avem
(2x1)+(3x1)^2+(4x1)^3=
2+3^2+4^3=
2+9+64=
=75