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0,08 amestec echimolecular de propena si 2 butena se oxideaza cu o solutie de K2Cr2O7, 0,1 M in mediu H2SO4.Substanta organica este dizolvata in 192,8 g
H2O.Sa se afle concentratia procentuala.
Va rog sa-mi dati si o explicatie.



Răspuns :

Amestec echimolecular => 0,04moli propena si 0,04moli 2-butena
1mol................................60g
CH2=CH-CH3 + 5[O] -> CH3-COOH + CO2 + H2O
0,04moli.........................2,4g
1mol.......................................2*60g
CH3-CH=CH-CH3 + 4[O] -> 2CH3-COOH
0,04moli.................................4,8g
macid=7,2g=md
ms=md+mapa=7,2+192,8=200g
c=md*100/ms=7,2*100/200=3,6%