65 g 2·36,5 g 2 moli
Zn + 2HCl → Zn[tex]Cl_2[/tex] + [tex]H_2[/tex]
x g 2·14,26 g y moli
[tex]c = \frac{m_d}{m_s} \cdot 100 \\ m_d = \frac{c \cdot m_s}{100} = \frac{10 \cdot 142,6}{100} = \frac{1426}{100} = 14,26 g[/tex] [tex]\text{HCl}[/tex]
[tex]M_{HCl} = 1+35,5 = 36,5 g[/tex]
[tex]x= \frac{2 \cdot 14,26 \cdot 65}{2 \cdot 36,5} = \frac{1853,8}{73} = 25,39 g[/tex] Zn
[tex]y = \frac{25,39 \cdot 2}{65} = \frac{50,78}{65} = 0,78 moli [/tex] H
