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Daca se stie x+2y=5 si a+3b=6,calculeaza 2x+4y+4a+12b si 8x+16y+8a+24b
Va rog ajutati-ma!


Răspuns :

2x+4y+4a+12b=2(x+2y)+4(a+3b)=2x5+4x6=10+24=34
daca x+2y=5 si a+3b=6 atunci:
a)2x+4y+4a+12b=2(x+2y)+4(a+3b)=2x5+4x6=10+24=34
b)8x+16y+8a+24b=8(x+2y)+8(a+3b)=8x5+8x6=40+48=88